Question by : 9th grade Algebra 1 Homework help ?
Im trying but i keep messing it up , help please ? Its Substitution and Elimination .
The School that Gabriella goes to is selling tickets to a play . On the first day of ticket sales the school sold 4 adult tickets and 7 child tickets for a total of 3.00 . The school took in 3.00 on the second day by selling 4 adult tickets and 5 child tickets . What is the price each of one adult ticket and one child ticket ?
Jennifer and Arjun each improved their yards by planting rose bushes and ornamental grass . They bought their supplies from the same store. Jennifer spent 4 on 6 rose bushes and 6 bunches of ornamental glass. Arjun spent on 3 rose bushes and 6 bunches of ornamental grass. What is the cost of one rose bush and the cost of one bunch of ornamental grass?
Best answer:
Answer by Gagan Manj
ad= 1 adult ticket
ct: 1 Child ticket
first day: 4 ad and 7 ct= 3
2nd day: 4 ad and 5 ct=3
4ad+7ct=133
(-)4ad+5ct=103
——————–
2ct=30
1 Child ticket equals 15 dollars, so subsitute the 15 into the second equation
4ad+5(15)=103
4ad+72=103
4ad=31
ad=7.75
So 1 Adult Ticket costs 7.75 dollars
Number 2 can be solved the above way.
Cheers!
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